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problem# h2chefor1 → Molar volume |
Atomic mass H =1 B = 11 C = 12 N = 14 O = 16 Na =23 Mg = 24 P = 31 S = 32 Cl = 35.5 K =39 Ca = 40 Br = 80 Ba = 137 Pb = 207 |
14. Consider the following gas at (STP)standard condition for temperature and pressure. i) Gas HCL 2.8 dm3 ii) Gas NO 6.02 x 1022 molecules. iii) Gas CO weight 3.5 g. iv) Gas NH3 11.2 dm3 Which one of the folllowing is incorrect? 1. The number of moles of gas HCL equals the number of moles of gas CO. 2. The number of molecules of gas NO is the least. 3. Volume of gas CO is 1.25 times of the volume of gas NO. 4. Gas NH3 occupies the least minimum pressure. |
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Photos credited bt Ratchamongkol |
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V = nRT/p → (1)
V = (1.00 mol)(0.0821 L atm/mol K)(273.15 K) / (1.00 atm)
Therefore; V = 22.4 L
Solution | ||||
From equation(1); we give A is the number of moles of HCl | ||||
1 mole
22.4 x 10-3 m3
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= |
A
2.8 x 10-3 m3
| ||
1 mole x 2.8 x 10-3 m3
22.4 x 10-3 m3
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= | A | ||
A | = | 0.125 mole | ||
(i) the number of moles of gas HCl in 2.8 dm3 | = | 0.125 mole | ||
(ii) the number of moles of gas NO | = |
the number of molecule of gas NO
NA
(Avogadro's number)
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||
⇒ | = |
6.02 x 1022
6.02 x 1023
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= | 0.1 mole |
(iii) the number of moles of gas CO | = |
mass of 1 mole of the compound(CO)
⇒ = 3.5/28
= 0.125 mole
(iv) the number of moles of gas NH3 11.2 dm3; | ||||
1 mole
22.4 x 10-3 m3
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= |
B
11.2 x 10-3 m3
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1 mole x 11.2 x 10-3 m3
22.4 x 10-3 m3
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= | B | ||
B | = | 0.5 mole | ||
(iv) the number of moles of gas NH3 11.2 dm3 is 0.5 mole | ||||
Comparing the volume of NO=0.1 mole and CO=0.125 mole | ||||
Find the volume of NO=0.1 mole; | ||||
1 mole
22.4 L
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= |
0.1
C
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C | = | 0.1 x 22.4 L |
Find the volume of CO=0.125 mole; | ||||
1 mole
22.4 L
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= |
0.125
D
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D | = | 0.125 x 22.4 L |
Volume of gas CO is 1.25 times of the volume of gas NO.
∴no. 3 is correct.
Ans.
no. 4 is incorrect. ∴we have the maximum number of moles of gas NH3
therefore,we can concluded that gas NH3 have the most pressure as well. |